If aspect ratio is being calculated using this, then 0.258/0.204 = 1.2647. For the shape on the right, this is 0.204. The software gives us the value for smallest caliper diameter, or MinFeret. The difficult question then, is what’s the smaller diameter being used to calculate aspect ratio? So it does seem that for Feret diameter, the software is indeed finding the largest diameter within the shape, which is what I want. Feret Angle is given as 65.966 degrees, which is quite a steep slope. Hovering my mouse over the image, that’s in the bottom left of the oval. Is this how Image J calculates aspect ratio?įor the shape on the right, the coordinates for Feret X and Feret Y are given as 770 and 907. (So aspect ratio is the ratio of the Feret diameter of the major axis, to the largest diameter of the minor axis). Where the minor axis is at a right angle to the major axis. An ellipse with an aspect ratio of 1:1 is a circle." " For an ellipse, the aspect ratio denotes the ratio of the major axis to the minor axis. This equation appears to simply be the above equation squared, but why would it be more appropriate to use a squared form of the equation for describing how spherical, or round, a particle is? However, when I checked how circularity is calculated in Image J, the equation was… The equation above makes sense to me, and the value would give us an idea of how spherical, or round, our particle is. So if we want the ratio of the circumference of an ideal circle to the circumference we actually got a software program such as image J, then the ratio would be In a paper, I saw a calculation for “sphericity,” which was basically a comparison between what the circumference would be for an ideal circle, and what the actual circumference was.
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